What is the fission of a covalent bond? Explain its types with examples and the main differences.

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(N/A) The fission of a covalent bond refers to the process of breaking a covalent bond. $A$ covalent bond can be cleaved in two ways:
$(i)$ Heterolytic cleavage
$(ii)$ Homolytic cleavage
| Feature | Heterolytic Cleavage | Homolytic Cleavage |
| :--- | :--- | :--- |
| $(i)$ Example | $H_3C-Br \rightarrow H_3C^+ + Br^-$ (forms positive and negative ions) | $H_3C-Br \rightarrow H_3C\cdot + \cdot Br$ (forms free radicals) |
| $(ii)$ Reaction Type | Ionic or polar reactions (nucleophilic or electrophilic) | Free radical or nonpolar reactions |
| $(iii)$ Mechanism | The shared pair of electrons remains with one of the fragments | One electron of the shared pair goes to each of the bonded atoms |
| $(iv)$ Intermediate | Forms carbocations or carbanions | Forms free radicals |

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What is the fission of covalent bonds?

The major product in the given reaction is :

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Write the homolytic and heterolytic fission of the $C-Br$ bond in $CH_3CH_2Br$.

Different possible thermal decomposition pathways for peroxyesters are shown below. Match each pathway from List-$I$ with an appropriate structure from List-$II$ and select the correct answer using the code given below the lists.
List-$I$:
$P$. Pathway $P$
$Q$. Pathway $Q$
$R$. Pathway $R$
$S$. Pathway $S$
List-$II$:
$1$. $C_6H_5CH_2CO_3CH_3$
$2$. $C_6H_5CO_3CH_3$
$3$. $C_6H_5CH_2CO_3C(CH_3)_2CH_2C_6H_5$
$4$. $C_6H_5CO_3C(CH_3)_2C_6H_5$
Codes:
$P \quad Q \quad R \quad S$
$A. 1 \quad 3 \quad 4 \quad 2$
$B. 2 \quad 4 \quad 3 \quad 1$
$C. 4 \quad 1 \quad 2 \quad 3$
$D. 3 \quad 2 \quad 1 \quad 4$

The major product in the following reaction is

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